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    Practice problems / Invert a binary tree

    Invert a binary tree

    Easytreedfsbfsrecursion

    Mirror the tree: swap the left and right child of every node. Return the root.

    Examples write a tree level by level, with null for a missing child: [3,9,20,null,null,15,7].

    Example 1

    Input:  root = [4,2,7,1,3,6,9]
    Output: [4,7,2,9,6,3,1]

    Example 2

    Input:  root = [2,1,3]
    Output: [2,3,1]

    Constraints

    • 0 ≤ number of nodes ≤ 100
    • -100 ≤ Node.val ≤ 100

    Submit checks your solution against 8 tests, including hidden ones.

    // Provided by the judge: keep these definitions
    class TreeNode {
      constructor(val = 0, left = null, right = null) {
        this.val = val
        this.left = left
        this.right = right
      }
    }
    
    /**
     * @param {TreeNode|null} root
     * @return {TreeNode|null}
     */
    function invertTree(root) {
      
    }
    
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